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The equation is this:
Wt = ae^gt
The t in Wt is subscript so i assume it doesn't make any difference to the equation i.e. 'Wt' would be the same as 'x'
e is the number e
W = 735
a = 1.0
g = 1.1
I need to rearrange to find t
If it helps I had to solve it to find Wt using 3 as t, this is how I did it
Wt = 1xe^(1.1x3)
Wt = 27.1

2007-05-18 04:39:17 · 7 answers · asked by Tim 2 in Science & Mathematics Mathematics

7 answers

Rearrange to:
Wt/ a = e^(gt)
take the natural log of both sides
ln(Wt/a) = gt
rearrange:
t = 1/g * ln(Wt/a)

2007-05-18 04:44:43 · answer #1 · answered by Blank 2 · 1 0

ok first move the a over. shouldn't be much of a problem since a = 1.0

then take ln on both sides. you should get
ln(Wt/a) = gt

so t = [ln(wt/a)]/g
numerically, t = 6.00 after rounding off

2007-05-18 11:45:04 · answer #2 · answered by ong_joce 2 · 1 0

W=ae^gt
W/a=e^gt
ln(W/a)=gt
ln(W/a)/g=t

natural log will cancel the exponential

2007-05-18 11:49:10 · answer #3 · answered by tuckerstyle 2 · 0 0

735=1xe^(1.1t): divide both sides by 1
735=e^(1.1t): take the natural log (ln) of both sides to eliminate e
ln(735)=1.1t: divide both sides by 1.1
ln(735)/1.1=t

That's how you solve for t.

2007-05-18 11:48:02 · answer #4 · answered by Cool Nerd At Your Service 4 · 0 0

W = ae^(gt)
W/a = e^(gt)
ln(W/a) = ln e^(gt)
ln(W/a) = gt
t = (ln(W/a))/g
t = (ln(735/1))/1.1 = 5.99988 approx = 6

2007-05-18 11:52:21 · answer #5 · answered by ironduke8159 7 · 0 0

W/a = e^(gt)
ln(W/a) = ln (e^(gt))
ln (W/a) = gt
t = (1/g).ln (W/a)
t = (1 / 1.1).ln (735)
t = 6

2007-05-18 14:02:42 · answer #6 · answered by Como 7 · 0 0

hmm, lets see.

Blank is correct above.

2007-05-18 11:46:40 · answer #7 · answered by Anonymous · 0 0

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