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A) sin (2pi/3)
B) sin (-pi/3)
C) sin (-5/6)
D) sin (5pi/6)
E) sin (-2pi/3)

2007-05-18 04:31:10 · 6 answers · asked by Lizzy B 1 in Science & Mathematics Mathematics

6 answers

A) sin 2pi/3 its the same angle in the 1st and 2nd quadrants

2007-05-18 04:36:57 · answer #1 · answered by bignose68 4 · 0 0

The answer is A.

There are several ways to show this, so here are a couple:

First of all, we know the sine refers to the height in the unit circle, and these two angles are at the same height of √3/2.

However, a much more impressive way to PROVE this is with a sum angle formula. The following is ALWAYS true:

sin(x+y) = sin(x)cos(y) + cos(x)sin(y)

So we know that 2pi/3 = pi/3 + pi/3, so make these x and y.

Therefore,

sin(pi/3 + pi/3) = sin(pi/3)*cos(pi/3) + cos(pi/3)+sin(pi/3),

and we know that cos(pi/3) is 1/2, so we have

sin(2pi/3) = (1/2)sin(pi/3) + (1/2)sin(pi/3) = sin(pi/3)

2007-05-18 11:43:35 · answer #2 · answered by C-Wryte 3 · 0 0

pi/3 is a third of the way to 180 degrees or pi. 1/3 of 180 is 60 degrees. Sin(60) is sqrt(3)/2. That's only possible in the first and forth quadrint. That means 60 degrees below 0 or in th negative direction is equal to pi/3.

B. sin(-pi/3)

2007-05-18 11:37:09 · answer #3 · answered by Cool Nerd At Your Service 4 · 0 1

A) sin (2pi/3)

2007-05-18 11:41:37 · answer #4 · answered by ironduke8159 7 · 0 0

A

NOT B
sin(-pi/3) = -sin(pi/3).

2007-05-18 11:37:40 · answer #5 · answered by joncummins1968 4 · 0 0

A

2007-05-18 11:37:57 · answer #6 · answered by PeteRock 2 · 0 0

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