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In the expansion of (a+b)^8, what is the value of the exponent, k, in the term that contains, (a^5)(b^k)?

a) 5
b) 56
c) 4
d) 3

2007-05-18 03:22:14 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

The exponents need to add to 8.

So, if you have a^5, then you have b^(8-5) = b^3

So, k = 3

2007-05-18 03:26:26 · answer #1 · answered by Mathematica 7 · 1 0

3

2007-05-18 10:26:41 · answer #2 · answered by Goddess of Grammar 7 · 0 0

The coefficients of the expansion will be:
1, 8, 28, 56, 70, 56, 28, 8, 1

Starting off at column zero and counting out to column 5, you get 56. The value 56 will be in column 3 coming back the other way, so it's power value will be three.

→(a^5)(b^3)

2007-05-18 10:45:09 · answer #3 · answered by Sparks 6 · 0 0

This one's so easy, you should do it yourself.

Try (a+b)^2. What do you notice about the powers of a and b in each of the terms?

Now try (a+b)^3. Do you see a pattern developing?

You could try (a+b)^4 if you don't see it yet.

2007-05-18 10:27:53 · answer #4 · answered by ryanker1 4 · 0 0

binomial expansion yields each term as
nCm*x^(n-m)*y^k....
so accordingly here,
n=8,
m=5....
so here k would be(8-5)=3..

2007-05-18 10:46:12 · answer #5 · answered by jadoo 2 · 0 0

c) 4

2007-05-18 10:27:52 · answer #6 · answered by wilmer 5 · 0 2

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