Intergral of 2/(sin^2x)?

1 ⤊

I know how to integrate sinx but I am confused with this.
Intergral of 2/(sin^2x)

2007-05-18 02:17:50 · 2 answers · asked by Asystole 1 in Science & Mathematics ➔ Mathematics

1/(sin(x))^2 = (csc(x))^2
Then
Integral (1/(sin(x))^2)=Integral (csc(x))^2 = -cota(x) + C

Or in your case
= 2(-cota(x)) + C

2007-05-18 02:40:38 · answer #1 · answered by Edward 7 · 1⤊ 0⤋

2/(sin^2x)=2csc^2x
since d/dx {-cotx} = csc^2x,
Integral 2csc^2x = -cot x + C

2007-05-18 02:40:16 · answer #2 · answered by jenrobrody 2 · 0⤊ 0⤋