2007-05-16 15:43:32 · 4 answers · asked by ah_bell 1 in Science & Mathematics ➔ Engineering
Without worrying about the load or work the output voltage has to do, it is simply a voltage divider.
__________________________R2
Voltage divider equation: Vin ------------ = Vout
________________________R1 + R2
This is my resistor symbol: -----vvvvv---- in ohms.
___________________________ 3.6 volts
___________________R1 = 100__ | __R2 = 360
Circuit: Vin = 4.6 volts ------vvvvv-------o------vvvvv----- GND
To prove this, plug in the values in the equation above.
2007-05-16 17:01:49 · answer #1 · answered by Richard N 1 · 0⤊ 0⤋
How much current do you need, and is the current draw constant? if the current is quite small and constant you might be able to use a resistor divider . Maybe a zener regulator could be used, but the voltage might be a bit hard to find. If the current is significant you'll probably want to use a low dropout IC regulator
2007-05-16 23:19:02 · answer #2 · answered by tinkertailorcandlestickmaker 7 · 0⤊ 0⤋
Use resistors to split the input voltage of 4.5, and take the output at the split point. Choose appropriate values for the resistance of each.
2007-05-16 22:47:55 · answer #3 · answered by Bazz 4 · 0⤊ 0⤋
Even engineers should know better than use jive spelling. In engineering ESOL doesn't work. You need batteries, wire and a resistance.
2007-05-16 22:49:33 · answer #4 · answered by cattbarf 7 · 0⤊ 0⤋