On may 15th PLEASE DONT BUY GAS.
2007-05-14 05:50:46 · 14 answers · asked by mikentammy76 5 in Society & Culture ➔ Community Service
NO GAS...On May 15th 2007
Don't pump gas on may 15th
In April 1997, there was a "gas out" conducted nationwide in protest of gas prices. Gasoline prices dropped 30 cents a gallon overnight.
On May 15th 2007, all internet users are to not go to a gas station in protest of high gas prices. Gas is now over $3.00 a gallon in most places.
There are 73,000,000+ American members currently on the internet network, and the average car takes about 30 to 50 dollars to fill up.
If all users did not go to the pump on the 15th, it would take $2,292,000,000.00 (that's almost 3 BILLION) out of the oil companies pockets for just one day, so please do not go to the gas station on May 15th and let's try to put a dent in the Middle Eastern oil industry for at least one day.
If you agree (which I can't see why you wouldn't) resend this to all your contact list. With it saying, "Don't pump gas on May 15th"
2007-05-14 06:11:49 · update #1
The prices for gas here are 3.40 a gallon .
2007-05-14 06:32:16 · update #2
I WILL NOT BUY GAS ON THE 15TH!!!!!!!!!!!!!!
2007-05-14 08:09:00 · answer #1 · answered by Debra B 1 · 1⤊ 0⤋
This has been going around and around forever and it makes NO sense to do this!!
It makes no sense because it doesn't lower demand at all.
If you don't buy gas on May 15th, you're just going to buy that gas on May 14th or on May 16th. You're still using the exact same amount of gas.
The only way this would work is if we all didn't USE gas on May 15th, and walked, biked, or took the bus to work. That would reduce demand (though not by that much).
Not buying gas on May 15th - if I was a gas station owner, I'd just raise prices on May 16th! Because I'd potentially have double the customers that day.
And it won't hurt the oil companies at all.
2007-05-14 06:04:43 · answer #2 · answered by Anonymous · 0⤊ 1⤋
Yeah right, it's not going to make a huge impact...because we all need gas to go to work, and I don't buy on the 15th, I'll need to buy it on the 17th....
some guy sent me an email to stop buying gas from a certain gas station and it won't work also. If they lower the price, then more people will pump at their station, in thus raising the price to it's original $3.50 a gallon.
I'm just being realistic
2007-05-14 05:54:40 · answer #3 · answered by Not_Here 6 · 2⤊ 1⤋
The only way to reduce cost is to reduce LONG TERM use. We need to reduce consumption and dependency, not just boycott the gas stations for one day. People will just fill up today or Wednesday, which means the same amount of gas is being sold - boycotting for one day will do NOTHING. There was NO successful 'gas out' in 1997 either.
2007-05-14 05:53:46 · answer #4 · answered by They call me ... Trixie. 7 · 3⤊ 1⤋
No, I think higher gas prices are better for the environment, especially since they seem to spur investment in alternative fuels. Also they discourage people from buying uselessly large trucks and obnoxiously big SUVs, which pollute more as well as clogging the streets and creating safety hazards for everyone else on the road.
2007-05-14 05:55:16 · answer #5 · answered by TheEconomist 4 · 2⤊ 0⤋
gas prices are still too low. they need to be in the neighborhood of $5 per gallon to have any real impact on the behavior of the consumers.
2007-05-14 06:25:31 · answer #6 · answered by Yahoo admins are virgins 5 · 0⤊ 1⤋
i dont have a car and i probably wont get one when im 16 cause of gas prices.
2007-05-14 05:54:12 · answer #7 · answered by angel_dust_23 4 · 1⤊ 0⤋
Yea, so they will raise gas prices the day after.
IT won't work.
2007-05-14 05:58:18 · answer #8 · answered by unan1m0us 5 · 0⤊ 1⤋
ya i really want the reduction in prices of gas
2007-05-14 06:35:13 · answer #9 · answered by santosh5002003 3 · 1⤊ 0⤋
Too late, just filled up today to avoid higher cost this week.
2007-05-14 05:53:19 · answer #10 · answered by Anonymous · 0⤊ 1⤋
Okay, I wont buy gas all week, its already full.
2007-05-14 05:53:05 · answer #11 · answered by Anonymous · 1⤊ 0⤋