How much a mole of austenite in stainless steel weigh in gram?

Question

How much a mole of austenite in stainless steel weigh in gram? what is its density? (approximates are fine)

Answer 1

If we consider a "mole" of austenite to be a quantity containing a Avogadro's number of atoms (of whatever element) then you can come up with an answer.

Suppose the composition of the Austenite is
atom fraction x chromium
atom fraction (1-x) iron

Then the "formula" of the material would be Fe(1-x)Cr(x)
and the mass would be
the mass of (1-x) moles of iron
plus the mass of x moles of chromium.

You will get approximately the right density by asuming the volume of the austenite equals the sum of the volumes of each component if pure (and dividing by the total mass above).

There might be other elements in the mixture, especially nickel in significant amounts, and you need to include the in the calculation too.

If you only need a very approximate estimate of the density, 7800 kg/cubic metre might be good enough.

Answer 2

Austenite is steel or Iron containing carbon and/or other elements and having a characteristic face-centered crystalline structure. It has sufficient nickel and chromium or manganese to retain the austenitic structure at atmospheric temperatures. It is named after the UK metallurgist Sir W. C. Roberts-Austen.

Austenite is the definition of the structure or arrangement of the grains within the steel, it cannot be measured in moles.