Earned runs allowed x nine, divided by innings pitched.
Example: 4 ER x 9 = 36 divided by 9 innings = 4.00 ERA
Say a pitcher allows 4 earned runs in only 7 innings. That would be: 4 x 9 = 36 / 7 = 5.14 ERA
Now let's say a pitcher has a fraction of an inning, 1/3 or 2/3.
Example: 4 x 9 = 36 / 6 2/3. Here's where you multiply two numbers by 3. (36) becomes 108, and 6 2/3 becomes 20, (because that's how many out he got). So 108 / 20 becomes 5.40.
There's one more. The first game of the year and the starting pitcher gives up 4 earned runs in the first inning and gets only one batter out. Now you multiply two numbers by 3.
Example: 4 x 9 = 36 / 1/3 becomes - 36 x 3 = 108 / 1 = 108.00 ERA.
Say he gets two outs: 4 x 9 = 36 / 2/3 becomes - 36 x 3 = 108 / 2 = 54.00 ERA.
Okay, one step further. He gets no outs. This one is outta sight, but only lasts until he gets a few batters out.
4 x 9 = 36 / 0 becomes 36 x 27 (because that's how many outs in a regulation game) = 927.00 ERA.
Two last examples to show how 1/3 of an inning will change a pitcher's ERA.
32 earned runs in 77 innings: 32 x 9 = 288 / 77 = 3.74.
32 x 9 = 288 x 3 = 864 / (77 1/3 x 3) 232 = 3.72.
2007-05-12 18:33:06
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answer #1
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answered by Jay9ball 6
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ERA is a pitching stat, used to help to determine a pitcher's effectiveness.
Earned Runs / Innings Pitched *9
You'll find more defintions, information, stats etc on the links below.
2007-05-12 18:38:52
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answer #2
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answered by Anonymous
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Earned runs given up per nine innings pitched.
Earned runs multiply 9 over innings pitched.
ERA gives you the average earned run total as it takes into account innings pitched.
2007-05-12 18:19:46
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answer #3
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answered by Arun K 4
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Earned runs given up multiplied by nine, then take that number and divide it by the number of innings pitched.
2007-05-12 18:19:21
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answer #4
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answered by et2reid 2
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(ER * 9) / IP, but it's usually easier to just look it up.
2007-05-12 18:18:04
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answer #5
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answered by Chipmaker Authentic 7
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