The question is:
(1/7/9)^1/2
Could someone please show me step-by-step how to solve the problem? Thanks.
2007-05-12 17:48:25 · 5 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
It's 1 and 7/9
2007-05-12 18:08:47 · update #1
√[1/7/9] = [1/(7/9)] = √[9/7] = ±3/√7
2007-05-12 18:03:59 · answer #1 · answered by Steve 7 · 0⤊ 0⤋
Wait a sec. Is it 1/(7/9)? or (1/7)/9? Well, here's both cases:
[1/(7/9)]^(1/2)
= [1*(9/7)]^(1/2)
= (9/7)^(1/2)
= â(9/7)
= ±3/(â7)
= ±(3â7)/7
[(1/7)/9]^(1/2)
= [1/63]^(1/2)
= â(1/63)
= ±1/(3â7)
= ±(â7)/21
1/7/9 is the same as (1/7)/9 (order of operations), so I won't write it out again.
2007-05-13 01:07:09 · answer #2 · answered by someone 3 · 0⤊ 0⤋
(16/9)^(1/2) = 4 / 3
2007-05-13 09:21:12 · answer #3 · answered by Como 7 · 0⤊ 0⤋
1/7/9=1/(7*9)
so
(1/(9*7))^1/2= 1/[(9^1/2)*(7^1/2)]=1/(3*sqrt7)
=sqrt7/21
2007-05-13 00:57:13 · answer #4 · answered by djin 2 · 0⤊ 0⤋
BODMAS
2007-05-13 00:56:44 · answer #5 · answered by chilly 3 · 0⤊ 0⤋