A light ray of wavelength 589 nm (produced by a sodium lamp) traveling through air is incident on a smooth, f?

Answer 1

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Answer 2

question B is a bad question. the wonderful answer is the wavelength of the photons would not exchange IF the colour would not exchange. So, assuming no shade exchange the wavelength remains 589 nm Why? it is the mechanism of how mild is transmitted by way of a sparkling fabric. Photons exist in elementary terms at c, so the rate of the photons would not exchange. yet..... the ordinary velocity of the photons is way less, and is the reason the Index of Refraction. What occurs is: The photons are absorbed by potential of the atoms of the fabric (the photons end). The electrons of the atom are excited elevating them to a much better ability point soaking up the flexibility of the photon. The electrons then fall returned to the floor state emitting a photon of the wonderful comparable frequency and wavelength of the photon that became into absorbed (the photons start up). the gap between atoms is loose area, so the photons pass c till they hit yet another atom. So, it is like using by way of a city with stoplights. The vehicles (photons) end at each and every mild (atom) and pass the fee cut back between lighting fixtures fixtures (c). So, the ordinary velocity is under the fee of the vehicles (photons).