aba - ca = ab?

Question

this is a freaking hard problem i cant understand.
what is the value of a?b?c?

it is
aba - CA
not
aba - ab

Right now i belive that B = 0
------------
aba
- ca
ab
---------------
so a number minus itself equals zero so b is zero

Answer 1

Are a,b,c suppose to represent digits in a number? If so, A=1, B=0, C = 9

ABA
- CA
-------
AB

A - A = 0, so B = 0.

AB - C = A, we know that A = 1, because otherwise, the final result would be a two digit number. So now we have:

101 - C1 = 10

101 - 10 = 91, so C = 9.

Answer 2

aba - ca = ab

Divide all by ab

a - c/b = 1

ie a = 1 + c/b

So the value of a is dependent on the values of b and c

NOTE:
1. b ≠ 0
2. If c = 0 then a = 1
3. If c = -b then a = 0 This is disallowed as we divided by ab and that would be a division by 0
So b + c ≠ 0

Answer 3

is the actual problem
Aba-ca=bc
or aba-ca
cuz if its the top one
then you would have to be like
axbxa-cxa=bxa
so a could be 2
be could be 3
c could be five and you would try it like that....but if its the other one i have no clue at all

Answer 4

ca=aba-ab
or ca=ab(a-1)
so c=b(a-1)

Answer 5

aba - ca = ab
a(b - c) = b
a = b over b-c

aba - ca = ab
aba - ab = ca
b(aa - a) = ca
b = ca/a
b = c
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Answer 6

a²b - ca = ab
ab - c = b
ab = b + c
a = (b + c) / b

a²b - ca = ab
a²b + ab = ca
b(a² + a) = ca
b = ca / (a² + a)
b = c / (a + 1)

a² - ca = ab
ca = a² - ab
ca = a.(a - b)
c = a - b

Answer 7

a-c/b=1
a=1+c/b