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1) Convert from rectangular to polar: x² + y² - 2x + 4y = 0.
2) From Polar to Rect.: (2, 4π/3)
3)Classify graph of xy + 5=0
4)Determine an equation for the hyperbola with center (0,-3), one vertex (0,-5) and one focus (0,3).
5)Find the equation of the ellipse with minor axis of length 6 and vertices (-9,3) and (7,3)
6)Find one focus for the ellipse: 9x²+25y²-36x-50y+60=0
7)Find the eccentricity of 9x²+4y²+36x-24y+36=0
8)Find the horizontal asymptote of the graph: f(x): = 6/(x-5)
thank you for your time!!!!

2007-05-12 17:23:36 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

This is not Homework, just help me do these problems I'll appreciate it, thank you!!!

2007-05-12 17:36:23 · update #1

4 answers

1) Convert from rectangular to polar: x² + y² - 2x + 4y = 0.
r^2 - 2rcosθ + 4rsinθ = 0
r^2 - 2r(cosθ - 2sinθ) = 0
r = 2(cosθ - 2sinθ)
r = 2√5cos(θ - 6π/17)

2) From Polar to Rect.: (2, 4π/3)
x,y = (-1,-√3)

3)Classify graph of xy + 5=0
hyperbola

4)Determine an equation for the hyperbola with center (0,-3), one vertex (0,-5) and one focus (0,3).

5)Find the equation of the ellipse with minor axis of length 6 and vertices (-9,3) and (7,3)

(1/256)(x + 1)^2 + (1/36)(y - 3)^2 = 1

6)Find one focus for the ellipse: 9x²+25y²-36x-50y+60=0

9(x^2 - 4x + 4) - 36 +25(y^2 - 2y + 1) - 25 + 60 = 0
9(x^2 - 4x + 4) +25(y^2 - 2y + 1) = 1
9(x - 2)^2 +25(y - 1)^2 = 1
c^2 = 1/9 - 1/25 = (25 - 9)/225 = 16/225 = 4/15
f = (34/15,1)


7)Find the eccentricity of 9x²+4y²+36x-24y+36=0

9(x + 2)^2 - 36 + 4(y - 3)^2 - 36 + 36 = 0
(1/4)(x + 2)^2 + (1/9)(y - 3)^2 = 1
a = 2, b = 3
e = 2/3

8)Find the horizontal asymptote of the graph: f(x): = 6/(x-5)
0

2007-05-12 18:36:40 · answer #1 · answered by Helmut 7 · 0 0

No I'm not really bored.

2007-05-12 17:25:48 · answer #2 · answered by Dr D 7 · 0 0

http://answers.yahoo.com/question/index;_ylt=AvPNBiZjozaDV1YGOueTtdoCxgt.?qid=20070512212250AAqvnVa

2007-05-12 17:27:13 · answer #3 · answered by Lostfairytale 2 · 0 0

I'm not that bored .................. yet ................ !!!!!!!!

2007-05-12 17:32:00 · answer #4 · answered by Mari C 3 · 0 0

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