2007-05-12 12:49:17 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(13x + 11y)^2
I did this by taking the square roots of the first and last one, since I knew that they were both perfect squares and then I knew that I had to add them because there were no negatives. Squaring all of that gave me the correct answer and to verify it was correct I factored it out!
I hope I helped
2007-05-12 12:52:05 · answer #1 · answered by Icobes 2 · 0⤊ 0⤋
Believe it or not, this is (13x+11y)².
One can guess at this from the facts
that 13² = 169 and 11² = 121.
Since 2*13*11 = 286, the result follows.
2007-05-12 21:32:34 · answer #2 · answered by steiner1745 7 · 0⤊ 0⤋
Given expression
=(13x)^2+2*13x*11y+(11y)^2
=(13x+11y)^2
2007-05-12 19:53:19 · answer #3 · answered by alpha 7 · 0⤊ 0⤋
169x^2 + 286xy + 121y^2
(13x+11y)^2
2007-05-12 21:01:48 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
(13x+11y)^2
2007-05-12 22:44:40 · answer #5 · answered by sam 3 · 0⤊ 0⤋
use my factoring calculator at http://www.poodwaddle.com/mathfactor.html
2007-05-12 20:20:06 · answer #6 · answered by shanusav 2 · 0⤊ 0⤋
(13x+11y)(13x+11y) or (13x+11y)^2
2007-05-12 19:52:13 · answer #7 · answered by brad p 3 · 0⤊ 0⤋