(8-2i)(6-4i)?

Answer 1

Expand & simplify the expression...

(8-2i)(6-4i)

First: eliminate parenthesis - use the Foil Method.

(8)(6)+(8)(-4i)+(-2i)(6)+(-2i)(-4i)
48+(-32i)+(-12i)+(8i^2)
48 - 32i - 12i + 8i^2

Sec: combine "like" terms in the middle.

48 - 44i + 8i^2

Third: the "i^2" becomes (-1) > replace (-1) with the "i" variable.

48 - 44i + 8(-1)
48 - 44i + (-8)
48 - 44i - 8
40 - 44i

Answer 2

For problems involving i, think of it as follows:

For * and /:
i * i = -1
1/i = (1*i)/(i*i) = -i

For + and -:
Group terms that have i and those that dont have i. Then add/subtract each group separately.

In your case if you multiply out, you get four terms:
8*6, -2i*6, 8*-4i, and -2i*(-4i)

The first is straightforward.
For the last use the multiplication formula for i:
-2 * i * - 4 * i gives you +8 * i * i which is +8*(-1) giving -8. this can be added to the first.

The middle two terms have a common factor of i - just add the real part times i:
i(-32 + (-12)) and you'll get the answer.

Answer 3

I take it the question is "Could somebody expand and simplify this for me?"

Multiply it just like the product of any other two binomials, only keeping in mind that i^2 = -1:

48 - 12i - 32i + 8i^2
48 - 44i - 8
40 - 44i

Answer 4

FOIL - First Outside Inside Last

48 - 32i - 12i + 8i^2

i^2 = -1

48 - 32i - 12i - 8

40 - 44i

Answer 5

(8-2i)(6-4i) use FOIL
48-32i-12i+8i^2 snce i^2=-1
48-8-32i-12i combine like terms
40-44i

Answer 6

= 48 - 32 i - 12 i + 8 i²
= 48 - 44 i - 8
= 40 - 44 i
= 4.(10 -11 i)

Answer 7

48 - 32i - 12i + 8i^2
48 - 44i - 8 (i^2 is -1)
40 - 44i
4(10 - 11i)

Answer 8

48-32i-12i+8i2
i squared = -1
48-44i+ 8(-1)
48-44i-8
40-44i

Answer 9

(8-2i)(6-4i)
48-32i-12i+8i^2
48-44i+8i^2

Answer 10

48-12i-32i+8i^2
48-44i+8i^2