An exployer discovered a treasure chest. It contained 150 bags of silver coins. He got to keep 1/3 of the bags of coins. How many bags did he get to keep?
2007-05-12 12:11:11 · 6 answers · asked by jruby 1 in Science & Mathematics ➔ Mathematics
An explorer discovered a treasure chest. It contained 150 bags of silver coins. He got to keep 1/3 of the bags of coins. How many bags did he get to keep?
First: multiply the whole number with the fraction.
(150)(1/3)
Sec: convert the whole number into a fraction > place 150 over 1.
(150/1)(1/3)
Third: combine the fractions.
150/3
= 50 bags
2007-05-12 17:05:59 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0⤊ 0⤋
1/3 x 150/1= 150/3= 50 bags
2007-05-12 19:15:24 · answer #2 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
150*(1/3)=150/3=50 bags
he kept 50 bags.
2007-05-12 21:06:27 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
50.
Because you keep 1/3 of the 150 bags, the equation would look like:
(1/3) * 150
This is similar to 150 divided by 3.
150 / 3 = 50 bags.
2007-05-12 19:14:37 · answer #4 · answered by Anonymous · 0⤊ 0⤋
50 bags
2007-05-12 19:18:38 · answer #5 · answered by robdhighway61 2 · 0⤊ 1⤋
50 bags
2007-05-12 19:14:28 · answer #6 · answered by swimmer09 1 · 0⤊ 1⤋