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In 2000, there were about 2,172,000 farms in the United States. Forty -four thousand of the farms were in Florida. What percent of the farms were in Florida? Round your answer to the nearest whole percent. Use this formula a=p% x b

2007-05-12 09:23:08 · 8 answers · asked by king_danio_84 1 in Education & Reference Homework Help

8 answers

a= 44000
b=2172000
p% = 2.0258%

44000/2172000=0,020258 x 100(toget the %)=2.0258%

2007-05-12 11:37:22 · answer #1 · answered by Dave aka Spider Monkey 7 · 0 0

44,000= p x 2,172,000 p= % of farms in Florida

44,000/2,172,000= p

.02026 or 2.00%= p multiply by 100 to get percentage

2007-05-12 18:13:10 · answer #2 · answered by cincykid8000 1 · 0 0

whoa
thats a toughie
can you say what a p and b stands for
im a whiz in math but i forget those
does the p go with the %

2007-05-12 16:49:56 · answer #3 · answered by Anonymous 2 · 0 0

44000/2172000 x 100 =2.03%

2007-05-12 16:31:34 · answer #4 · answered by rabies1979 3 · 0 0

the answer should be around 2%

2007-05-12 16:43:10 · answer #5 · answered by docwiggles0315 1 · 0 0

well, your answer should be 2.03%, but you said to round it, so about 2%

2007-05-12 16:51:02 · answer #6 · answered by sarahbara_sarahali 2 · 0 0

44000/2172000*100=2.03%

2007-05-12 16:42:36 · answer #7 · answered by Anonymous · 0 0

44,000 / 2172000 = percent.

2007-05-12 16:28:02 · answer #8 · answered by Anonymous · 0 0

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