3z-5<=3z-13
2007-05-12 08:04:46 · 5 answers · asked by Micro spice 3 in Science & Mathematics ➔ Mathematics
its undifined because when you subtract 3z from both sides it cancles out and you have -5 <= 13
2007-05-12 08:08:42 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3z - 5 <= 3z - 13
-5 <= -13 (subtract 3z from both sides)
now is this true? is -5 less than or equal to -13? well, no
so no matter what z you stick into this inequality, it will never be true.
answer is "no solution"
2007-05-12 15:11:29 · answer #2 · answered by itsakitty 3 · 0⤊ 0⤋
No real answer. Subtract 3z from both sides and it gets messed up, even though subtracting 3z from both sides was a perfectly legal algebraic move.
2007-05-12 15:12:37 · answer #3 · answered by Spearfish 5 · 0⤊ 0⤋
3z <= 3z -8.
If Z>0, 3Z-8 will be less than 3Z
If Z=0, -8 is less than 0
If Z<0, 3Z-8 will be less than 3Z
There is no such z that will satisfy this condition.
2007-05-12 15:16:58 · answer #4 · answered by Welcome to Vancouver 3 · 0⤊ 0⤋
3z-5<=3z-13
3z-3z-5<=3z-3z-13
0z-5+5<=-5+5-13
0z<=-8
undefined
2007-05-12 15:54:40 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋