English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Hi, I need help with the following exercise:

We have a square circuit, with 4 capacitors, 1 on each side of the square, all with the same capacitance C. Calculate the total capacitance of the system of capacitors between the two diagonally opposite corners of the square, A and B.

This is how I solved it, could you tell me if it's right?

A ) 2 capacitors (from A to B ): they are in series
B ) 2 capacitors (from B to A): they are in series

A )1/Ceq = 1/C1 + 1/C2= 2/C --> A-Ceq=C/2
B )1/Ceq = 1/C3 + 1/C4= 2/C --> B-Ceq=C/2

Now A-Ceq and B-Ceq are in a parallel configuration:

C) Ceq = C/2 + C/2 = C

The total capacitance is equal to C?

Thank you.

2007-05-12 02:57:53 · 3 answers · asked by deluca.claudia 1 in Science & Mathematics Physics

3 answers

100% correct. Good job !

2007-05-12 03:13:50 · answer #1 · answered by Gene 7 · 0 0

Correct

2007-05-12 03:20:37 · answer #2 · answered by Anonymous · 0 0

You did GOOD !

2007-05-12 03:20:56 · answer #3 · answered by Steve 7 · 0 0

fedest.com, questions and answers