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Question #24
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Find all values of t satisfying the equation.

-16\t^2-2t-8=4t\t+2

2007-05-10 20:33:05 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

t = 2.

factor denominator on left.

cross multiply.

then set equal to zero and simplify.

then solve.

2007-05-10 20:42:36 · answer #1 · answered by mr green 4 · 0 0

-16\t^2-2t-8=4t\t+2
-16 / (t - 4) (t + 2) = 4t / (t + 2)
-16 / (t - 4) = 4t
-16 = 4t (t - 4)
4t^2 - 16 t + 16 = 0
4 (t^2 - 4t + 4) = 0
(t - 2) (t - 2) = 0

therefore:
t - 2 = 0
t = 2

2007-05-10 21:17:40 · answer #2 · answered by aquarian8502 2 · 0 0

(-16) / (t - 4).(t + 2) = 4t / (t + 2)
(-4) / (t - 4) = t
(-4) = t² - 4t
t² - 4t + 4 = 0
(t - 2).(t - 2) = 0
t = 2 (twice)

2007-05-11 22:18:59 · answer #3 · answered by Como 7 · 0 0

when would you like to catch up????
Currently I'm at UWS Library internet at 5:40pm

2007-05-10 20:36:55 · answer #4 · answered by thur03joanne 3 · 0 0

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