area enclosed by pair of lines xy=0,the ,line x-4=0and y+5=0 is----------------?

Answer 1

Find the area enclosed by pair of lines xy = 0, the line
x - 4 = 0 and y + 5 = 0.

xy = 0 is two lines.
x = 0 and y = 0

The other lines are:
x - 4 = 0
x = 4

And
y + 5 = 0
y = -5

Pretty clearly we have a 4 by 5 box.

The area is 4*5 = 20

Answer 2

The answer is 20 square units.

The pair of lines to which they refer are the x and y axis. Given the equation xy = 0, we must allow for the possibility that either x or y may be 0. So, if -∞ ≤ x ≤ ∞, then y = 0 for all x because x(0) = 0. Similarly, if -∞ ≤ y ≤ ∞, then x = 0 for all y because y(0) = 0. So, the x and y axis form two sides of the the enclosed area.

The other two lines which form the boundary are the equation x - 4 = 0, which implies x = 4 and y + 5 = 0, which implies y = -5. Now we have a box which is x = 4 units wide and y = |-5| units long. We take the absolute value of y because area is never a negative quantity when using real numbers.

Now we use the formula for area, A = lw, to find the area of this enclosed region.

A = |-5| units x 4 units = 20 units²

Answer 3

looks like 3 lines not a pair, which would give you a triangle, no?