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Make one side equal to other.

2007-05-10 18:06:44 · 5 answers · asked by James Z 1 in Science & Mathematics Mathematics

5 answers

Let 5^[n-1] = k.
We have
4k = 5k -1, since 5^n=5*5^[n-1]
so k =1.
Hence
n-1=0;
n=1.

2007-05-10 18:11:16 · answer #1 · answered by Sceth 3 · 0 0

4^0 * 5^n-1 = 5^n - 1

2007-05-11 01:09:03 · answer #2 · answered by iyiogrenci 6 · 0 0

I don't see a point for making one side equal to another, did you mean to say "find a solution for the equation"?

Taken literaly, you can multiply both sides by zero, then they will be equal:
0 * (4 * 5^n - 1) = 0 * (5 ^ n - 1)

2007-05-11 01:15:09 · answer #3 · answered by Roman G. 1 · 0 0

5^(n-1)=(5^n)/5

=> 4/5*(5^n)=5^n - 1
=> (-1/5)*(5^n)=-1
=> 5^n=5
=> n=1

2007-05-11 01:11:52 · answer #4 · answered by piyush k 1 · 0 0

it is equal justified by the '=' sign.

2007-05-11 01:21:56 · answer #5 · answered by Kuan T 2 · 0 0

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