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i think it is 1 / 2*(sqrt x+1) but i dont get how it would

2007-05-10 17:47:29 · 8 answers · asked by ph103 1 in Science & Mathematics Physics

8 answers

You want to find the derivative of (x+1)^(1/2) by the chain rule.

First find the derivative of the power using power rule. Multiply by the exponent and decrease the exponent by one. We get:

1/2 * (x+1)^(-1/2)

Next multiply by the derivative of the stuff inside the exponent (x+1) which equals 1. (Chain Rule)

Our final derivative is:

1/2 * (x+1)^(-1/2) or 1/(2*sqrt(x+1))

2007-05-10 17:59:47 · answer #1 · answered by msi_cord 7 · 0 0

1/2 * (x+1)

2007-05-11 00:56:03 · answer #2 · answered by Sumaiya S 2 · 0 0

i'll try to explain this one.

(sqrt of x + 1) is equal to (x + 1) raised to the 1/2 power.

According to derivative rules, you have to lower 1/2 and put it beside (x + 1), so that now it becomes 1/2(x + 1) [or in words, one-half times quantity x plus one].

I DON'T KNOW HOW THE RULE IS STATED BUT IT SOUNDS LIKE THIS: when you take the derivative of x raised to the nth power, multiply x by n and subtract 1 from n, so that now it becomes nx^(n-1) [or in words, n times x raised to the n - 1].

So we're not done yet. Going back to your problem, 1/2(x-1) now becomes 1/2(x-1) raised to the 1/2 - 1 or -1/2 [negative one-half]. Note that only (x-1) is raised to the -1/2 and 1/2 is not included.
so we now have, 1/2[(x-1)^(-1/2)].

Finally, (yes we're not done yet!) We have to take the derivative of (x-1) and multiply that to our last answer. It's called the chain rule. But since the derivative of (x-1) is just equal to 1, so our finally answer is indeed

1/2[(x-1)^(-1/2)], or in words, one-half times the quantity, x minus 1 raised to the negative one-half.

Hope you understood that. This one's relatively easy, though. Check out basic algebra books.

2007-05-11 01:06:12 · answer #3 · answered by neal lasta 2 · 0 0

1/2(x+1)^-1/2

2007-05-11 00:58:17 · answer #4 · answered by B B 1 · 0 0

derivative of (sqrt(x+1))

this can be rewritten as

(x+1)^1/2

using diff(x^n)=n*(x)^n-1

1/2(x+1)^(-1/2)

2007-05-11 01:36:42 · answer #5 · answered by jon d 3 · 0 0

d/dx (x + 1)^(0.5) = 0.5(x + 1)^(-0.5)

= 0.5/(x + 1)^0.5

Note that sqrt is equivalent to the -1/2 pwr and,

(x + 1)^(-1/2) = 0.5/(x + 1)^1/2

used 0.5 for 1/2 in the equation to keep it simple.


So your answer is correct.

2007-05-11 01:00:41 · answer #6 · answered by Matt D 6 · 0 0

___1___
2(sqrt x+1)

2007-05-11 01:00:47 · answer #7 · answered by Anonymous · 0 0

(X+1)^(0.5)

Derivative = 0.5*(X+1)^(-0.5)

2007-05-11 01:13:20 · answer #8 · answered by The Man 1 · 0 0

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