Okay, for algebra gurus, this should go by in the blink of an eye, but for me...ughh, well at least im passing 9th grade algebra with a 93%. Anyways, I need help on solving the last part of the problem, or I may have done it incorrectly?
well, the math problem (instuctions: perform indicated operations, then simplify) is...
2m/m-1 + m/2m-2
okay, you may answer the question, or you could be nice and read through my work, heck, it may save you the trouble of figuring the problem out!
I started by adding the numerators together to equal 2m
then i found the GCF (greatest commen factor) of the second denomenator = 2
and then i added m-1 with 2(m) to get 2(m-1)
this is where im stuck. My teacher gave me the answer of 5m/2(m-1) .... but where does the 5 come from?? thanks for helping!
2007-05-10 15:24:38 · 8 answers · asked by Mr.Domino 2 in Education & Reference ➔ Homework Help
you need to make the denominators equal to each other before you can add the numerators.
multiply the entire first fraction by 2 (numerator and denominator)
2(2m)/2(m-1) = 4m/2m-2 (remember the distributive property!)
so you will end up with 4m/2m-2 + m/2m-2
NOW add the numerators and you will get 5m/2m-2!!!
(which is the same as 5m/2(m-1))
2007-05-10 15:32:45 · answer #1 · answered by Mary 3 · 2⤊ 0⤋
First, multiply the 2m/(m-1) times 2/2 to get a common denomenator
you end up with
4m/(2(m-1) + m/2(m-1)
Then, add 4m and m to get 5m on top. keep the same denomenator and you end up with
5m/(2(m-1))
2007-05-10 15:35:00 · answer #2 · answered by Rainey B 2 · 0⤊ 0⤋
be glad I just learned this yesterday. LOL!
Okay.. what you do is you find the Least Common Multiple... & you should get
LCD: 2, (m-1)
So, you make each demoniator match.. so you times 2m/m-1 by 2 on the bottom... AND the top.
You should get 4m/2m-2 so now that both demoniator's match... you add them & you'll get 5m/2m-2
when your simplify the demoniator by 2, to look like your teacher's answer, it will be 5m/2(m-1)
so there you have it.
2007-05-10 15:33:58 · answer #3 · answered by punkbratbaby69 1 · 0⤊ 0⤋
turn dissimilar fractions into similar fractions..
in your problem's case you will need to find the GCF and you're correct. so you just have to rewrite it:
2m/m-1 + m/2m-2
change it to similar fractions using the GCF 2m - 2
and you will get
>> 4m / (2m-2) + m / (2m-2)
>> your numerators are 4m and 2 with a plus sign in between and yout denominator is 2m - 2
Just add your new numerators
4m + m = 5m
write it with its denominator:
=5m/ (2m-2)
2007-05-10 15:38:22 · answer #4 · answered by Autisteek 2 · 0⤊ 0⤋
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2016-09-05 16:50:07 · answer #5 · answered by agostinelli 4 · 0⤊ 0⤋
2m/m-1 + m/2m-2
2m /m-1 + m/ 2(m-1)
lcd is 2(m-1)
2(2m)+m= 5m/2(m-1)
4m+m=5m/ 2(m-1)
2007-05-10 15:37:13 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Check again............ the answer is .5 over 2(m-1)
notice the decimal point .5/2(m-1)
2007-05-10 15:55:00 · answer #7 · answered by tommyeureka 2 · 0⤊ 1⤋
(2m)/(m - 1) + (m)/(2m - 2)
(2m)(2m - 2)/(m - 1)(2m - 2) + (m)(m-1)/(2m - 2)(m - 1)
((2m)(2m - 2) + (m)(m - 1))/((m - 1)(2m - 2))
(4m^2 - 4m + m^2 - m)/(2m^2 - 4m + 2)
(5m^2 - 5m)/(2m^2 - 4m + 2)
That's pretty much as far out as you can go.
2007-05-10 15:39:09 · answer #8 · answered by Lapper 4 · 0⤊ 1⤋