Find the x and y intercept?

Question

I had to find the x and y intercept for this linear system:

x+y=4 (0,4) (4,0) = Answer
2x-y=2 (0,-2) (2,0) = Answer

How can I use those coordinates to find the point of intersection without GRAPHING...?

Thanks in advance
First correct answer gets 5-star best answer...

Answer 1

set both equations equal to y which means ull get
y=4-x and y=2x-2
now replace y in one with the other
4-x=2x-2
solve for x
4=3x-2
6=3x
2=x
now put x in to either one equation
y=4-2
y=2
both graphs intersect each other at (2,2)

Answer 2

You wrote: 2x--10=0 that's erroneous. 2x - 3(0) -10=0 2x - 10 = 0 2x = 10 x = 5 So the x intercept is 5. to locate the y-intercept, set x = 0 2(0) - 3y -10 = 0 -3y-10=0 -10 = 3y y = -10/3 So the y intercept is - 10/3 or -3 a million/3

Answer 3

To find the x and y intercepts of any equation just substitute 0 for x and solve the equation. This will give you the y intercept. Then, substitute 0 for y and solve the equation and it will give you the x intercept.

This works because when you put in zero as a point, it is on the axis, meaning it is an intercept

First Equation

x+y = 4
0 +y = 4
y = 4

x+y = 4
x+0 = 4
x = 4

Second Equation

2x-y = 2
2*(0) -y = 2
0-y = 2
y = -2

2x-y = 2
2x -0 = 2
2x = 2
x= 1

Answer 4

For the x intercept, substitute in a 0 for y and solve for x. the x intercept is then (x,0).
For the y intercept, substitute in a 0 for x and solve for y. the y intercept is (0,y).
For 1, substituting 0 in for y gives you x=4, x int is (4,0). Substituting 0 for x gives you y=4, so y int is (0,4).
Same concept for the second one.

Answer 5

When equations are in Standard Form (Ax+By=C)
Y-intercept always equals C/B
X-intercept always equals C/A
So if you had the line
x+y=4
Plug it in:
C/B= 4/1= 4. 4is the y-intercept
C/A= 4/1= 4. 4 is the x-intercept.

Also, slope is always -B/A

Answer 6

x + y = 4
2x - y = 2------ADD
3x = 6
x = 2

2 + y = 4
y = 2

Point of intersection is (2,2)

Answer 7

answer (2,2)