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2^x=0.5

4^x+5=0.5

4^2x-5=32

2007-05-10 13:41:58 · 2 answers · asked by luv4mysavior 2 in Science & Mathematics Mathematics

2 answers

Question 1
x log 2 = log 0.5
x = log 0.5 / log 2
x = 2.32

Question 2
Assume question should read:-
4^(x + 5) = 0.5
(x + 5).log 4 = log 0.5
(x + 5) = log 0.5 / log 4
x = - 5.5

Question 3
Assume question is:-
4^(2x - 5) = 32
(2x - 5).log 4 = log 32
(2x - 5) = log 32 / log 4
2x - 5 = 2.5
2x = 7.5
x = 3.75

2007-05-11 04:38:21 · answer #1 · answered by Como 7 · 0 0

2^x = 1/2
2^-1 = 1/2
x = -1
4^x = -4.5
x log 4 = log -4.5
no solution

4^2x = 37
2x log 4 = log 37
2x = 2.6
x = 1.3

2007-05-10 20:48:13 · answer #2 · answered by richardwptljc 6 · 0 0

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