2007-05-10 13:14:03 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
log 45 = log(3^2 times5)
log 45 = 2 log 3 + log 5
lg 45 = 2(1.4) + 3.6 = 6.4
2007-05-10 13:16:35 · answer #1 · answered by richardwptljc 6 · 0⤊ 0⤋
log 45
= log (3² * 5)
= log 3² + log 5
= 2log3 + log 5
= 2*1.4 + 3.6
= 2.8 + 3.6 = 6.4
2007-05-10 20:17:49 · answer #2 · answered by Kathleen K 7 · 0⤊ 0⤋
(1) log45 = log3 + log3 + log5
Remembering that we can use the addition of logs of numbers to accomplish multiplicatioN.
3*5*5 = 45 tale log of both sides and get equation (1) ABOVE
2007-05-10 20:20:44 · answer #3 · answered by Matt D 6 · 0⤊ 0⤋
log 45 is the same as
2log3+log5=6.4
2007-05-10 20:18:12 · answer #4 · answered by andrea c 4 · 0⤊ 0⤋
47.6 i think i used the calculator and subtracted 3.6 by 1.4 and got 2.2 so every 2 logs is 2.2 so add 2.2 to 3.6 untill you reach log 45.
3.6+2.2=5.8
log 5 (3.6) every log (2.2) = 5.8 which is log 7.
so i think it is 47.6
2007-05-10 20:26:31 · answer #5 · answered by Jake E 2 · 0⤊ 1⤋
just do 3.6 times 9
2007-05-10 20:21:54 · answer #6 · answered by SwimmerMan 1 · 0⤊ 1⤋
Wow. The exact same question twice. What an amazing coincidence. http://answers.yahoo.com/question/index;_ylt=Ake7H3sxIWGT71_cUtphxJrsy6IX?qid=20070510162411AA8FJdX&show=7#profile-info-pPVO3QHzaa
2007-05-10 20:22:07 · answer #7 · answered by Pascal 7 · 0⤊ 0⤋