2007-05-10 12:34:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Since 5 is prime, it can only be written as: 1x5.
6 can be written as: (1)(6), (-1)(-6), (2)(3), (-2)(-3).
Just looking you might notice that 5*3 - 1*2 = 13. This give the factorization
(5x - 2)(x + 3) = 0
Because there are no zero divisors, a*b = 0 implies a = 0 or b = 0.
5x - 2 = 0
5x = 2
x = 2/5
x +3 = 0
x = -3
Thus, by factoring we find that the two roots are 2/5 and -3.
2007-05-10 12:38:14 · answer #1 · answered by NSurveyor 4 · 0⤊ 0⤋
(5x-2)(x+3)
use FOIL to check
Firsts: 5x^2
Insiders: -2x Outsiders: 15x
lasts: -6
add the insides and outsides to get 13x
now put it in the FOIL order
5x^2+13x-6=0 is correct now that you know that is correct you have to set each set of parentases equal to zero
5x-2=0
5x=2
x=2/5
and the other one
x+3=0
x= -3
so your answers are
x= 2/5,-3
2007-05-10 12:38:17 · answer #2 · answered by :) 5 · 0⤊ 0⤋
(5x - 2).(x + 3) = 0
x = 2/5 , x = - 3
2007-05-11 04:26:10 · answer #3 · answered by Como 7 · 0⤊ 0⤋
(5x - 2)(x + 3) = 0
x = 2/5, -3
2007-05-10 12:37:50 · answer #4 · answered by richardwptljc 6 · 0⤊ 0⤋