Okay,
8x^2-7=0
Using the quadratic formula... a=8 b=? c=-7
what would "b" be and why? is it zero?? if so, why?
2007-05-10 12:32:31 · 7 answers · asked by xrandomnessx 2 in Science & Mathematics ➔ Mathematics
b = 0, you could write the equation as
8x² + 0x - 7 = 0
if you wanted.
2007-05-10 12:35:30 · answer #1 · answered by Mαtt 6 · 1⤊ 0⤋
Your question is about the coeficient of x.
The General Form of the Quadratic Equation is
= a x^ 2 +b x + c.
Given equation
= 8 x ^2 + 0 x -7 =0
The Coefficient of the term x^2 = a = 8
There is no x term. So the coefficient of x term = b = 0.
Reason: If there is a value for b other than zero, the x term will be there & won't be missing.
The constant term = c = - 7
Think, it is made clear enough.
Where is my tenner?
2007-05-10 19:37:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A quadratic equation is of the kind a*x^2+b*x+c=0 So b is in fact zero in this case
2007-05-10 19:36:00 · answer #3 · answered by Guilherme Costa 2 · 0⤊ 0⤋
Yeah, b would be 0...You get the numbers a, b, and c from the coefficents of the terms, and for c the constant (ax^2 + bx + c). Since x isn't there at all, it means that b is 0, because when you multiply x by zero, clearly you get 0 and it won't be there.
2007-05-10 19:36:56 · answer #4 · answered by ajfmf90 2 · 0⤊ 0⤋
Let's rewrite this explicitly in standard form:
8x² + 0x + (-7) = 0
So yes, b is 0, because that is the coefficient of x.
2007-05-10 19:35:49 · answer #5 · answered by Pascal 7 · 0⤊ 0⤋
yes it is 0
2007-05-10 19:37:05 · answer #6 · answered by :) 5 · 0⤊ 0⤋
b equals zero
2007-05-10 19:36:01 · answer #7 · answered by mazzax 1 · 0⤊ 0⤋