2007-05-10 12:24:11 · 10 answers · asked by yikodi 1 in Science & Mathematics ➔ Mathematics
This basically tests your understanding of the laws of logarithms: log 45 = log (3²*5) = 2 log 3 + log 5 = 2*(1.4) + 3.6 = 6.4
That said, I should point out that there is no possible base that you could choose so that log 3=1.4 and log 5=3.6 . The log function is monotone, so if the base is greater than 1 (which it must be for log 3 to be positive), log 9 > log 5, but according to this assignment log 9 = 2.8 < 3.6 = log 5! Clearly, the problem suffers from a lack of realism.
2007-05-10 12:32:05 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
Log[45]=Log[3*3*5]=
=Log[3]+Log[3]+Log[5]=1.4+1.4+3.6=6.4
2007-05-10 19:27:38 · answer #2 · answered by Guilherme Costa 2 · 0⤊ 0⤋
45=3*3*5 log abc=log a + log b + log c so
log 45=log 3 + log 3 + log 5
log 45=1.4+1.4+3.6=6.4
2007-05-10 19:30:02 · answer #3 · answered by yupchagee 7 · 0⤊ 0⤋
log 45 = log (3^2 times 5)
log 45 = 2log 3 + log 5
log 45 = 2(1.4) + 3.6 = 6.4
2007-05-10 19:27:54 · answer #4 · answered by richardwptljc 6 · 0⤊ 0⤋
log 45
= log (9 x 5)
= log (3² x 5)
= log 3² + log 5
= 2.log 3 + log 5
= 2.8 + 3.6
= 6.4
2007-05-11 06:59:40 · answer #5 · answered by Como 7 · 0⤊ 0⤋
log 45 = log 9*5
= log 9 + log 5
=log(3^2) + log 5
=2log3 + log 5
=(2*1.4) + 3.6
=2.8 + 3.6
=6.4
2007-05-10 19:34:13 · answer #6 · answered by Farid 1 · 0⤊ 0⤋
to multiply numbers you add their logs, thus to get 45 you would multiply 3 X 3 X 5 and thus you wouyld add the log of 3 + the log of 3 +_ the log of 5 and GET THE LOG OF 45
2007-05-10 19:28:11 · answer #7 · answered by ? 3 · 0⤊ 0⤋
add the logs.
45 is 5*3*3
so, log 45 = 3.6+1.4+1.4=6.4
2007-05-10 19:28:51 · answer #8 · answered by Your Best Fiend 6 · 0⤊ 0⤋
45 = 3*3*5
log 45 = 2log 3 + log 5
just do the addition
2007-05-10 19:28:10 · answer #9 · answered by cscokid77 3 · 0⤊ 0⤋
log 3*3*5= log3+log3+log5=2log3+log5=2*(1.4)+(3.6)
2007-05-10 19:29:16 · answer #10 · answered by Anonymous · 0⤊ 0⤋