If the area of a rectangle can be represented by x2 - 25, which could represent its length and width?
A.x-5, x-5
B.x squared, -25
C.5, 5
D.x-5, x+5
2007-05-10 12:22:29 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
D
(x-5)*(x+5) = x^2 -25
2007-05-10 12:25:34 · answer #1 · answered by cscokid77 3 · 0⤊ 0⤋
Area of the Rectangle A= Length * Width (or Breadth)= lb =
=x^2 - 25
Factorizing (x^2 - 25) or (x^2 - 5^2)
we get (x+5) * (x-5)
So Length = (x+5) units
Breadth (b) or width = (x-5) units
Correct answer =D
2007-05-10 12:35:28 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The product of the length and width must be the area of the rectangle. There is only one pair of numbers listed whose product is x²-25, and that is d: x-5 and x+5
2007-05-10 12:25:43 · answer #3 · answered by Pascal 7 · 0⤊ 0⤋
it's almost a factoring question:
x^2 - 25 = (x-5)(x+5)
that is D
2007-05-10 12:28:44 · answer #4 · answered by Farid 1 · 0⤊ 0⤋
I'm thinking it's D.
If you simplify this:
(x-5)(x+5)
(x*+5x-5x-25).......... [let * mean squared]
(x*-25)...............[because +5x - 5x, will equal 0, so you don't need the zero]
2007-05-10 12:26:44 · answer #5 · answered by Anonymous · 0⤊ 0⤋
D
2007-05-10 12:25:39 · answer #6 · answered by hhh 2 · 0⤊ 0⤋