Well, let's use a technique to find the exact square that meets this requirement. We will call the five digit perfect square x.
We know that the smallest 5-digit perfect square is 100^2 (10,000). Also, we know that 400^2 (160,000) is a 6-digit perfect square.
Therefore, 100^2 < x < 400^2.
Look at 300^2 = 90,000. Replace the lower term with that.
300^2 < x < 400^2
Look at the middle point here, 350^2 = 122,500. Replace the higher term.
300^2 < x < 350^2
Continue following this method to find the largest perfect square, using the midpoint each time.
325^2 = 105,625
300^2 < x < 325^2
312^2 = 97,344
312^2 < x < 325^2
318^2 = 101,124
312^2 < x < 318^2
315^2 = 99,225
315^2 < x < 318^2
317^2 = 100,489
315^2 < x < 317^2
The number that would meet this is 316^2 = 99,856.
2007-05-10 12:22:07
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answer #2
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answered by Jason P 4
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SQRT (99999) = 316.2
so 316 is the largest without producing a 6 digit number
2007-05-10 12:19:37
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answer #3
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answered by cscokid77 3
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