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2007-05-10 12:09:54 · 3 answers · asked by Antares 6 in Science & Mathematics Mathematics

3 answers

316² = 99856

2007-05-10 12:15:46 · answer #1 · answered by Pascal 7 · 1 0

Well, let's use a technique to find the exact square that meets this requirement. We will call the five digit perfect square x.

We know that the smallest 5-digit perfect square is 100^2 (10,000). Also, we know that 400^2 (160,000) is a 6-digit perfect square.

Therefore, 100^2 < x < 400^2.

Look at 300^2 = 90,000. Replace the lower term with that.

300^2 < x < 400^2

Look at the middle point here, 350^2 = 122,500. Replace the higher term.

300^2 < x < 350^2

Continue following this method to find the largest perfect square, using the midpoint each time.

325^2 = 105,625

300^2 < x < 325^2


312^2 = 97,344

312^2 < x < 325^2


318^2 = 101,124

312^2 < x < 318^2


315^2 = 99,225

315^2 < x < 318^2


317^2 = 100,489

315^2 < x < 317^2


The number that would meet this is 316^2 = 99,856.

2007-05-10 12:22:07 · answer #2 · answered by Jason P 4 · 1 0

SQRT (99999) = 316.2
so 316 is the largest without producing a 6 digit number

2007-05-10 12:19:37 · answer #3 · answered by cscokid77 3 · 0 0

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