solving 2 step equation?

Question

how to solve 2 step equation like 7h+1= -13 and a equation with veriable on both side like this x+4+x-2= 6

can you show me the steps is there any short way of finding the answers out is there a easy way?

Answer 1

You solve these by a series of step, each of them leading you to a different equation that still holds and follows the original equation.
Each step typically constitutes in either adding or subtracting a number to both sides (either constant or variable), or multiplying both sides with a number that differs from 0. Later on you can go into things as square root and so on, but there are certain strings attached there.

So let's go over the first one:
7h + 1 = -13
First, let's subtract 1 from both sides.
7h + 1 - 1 = -13 - 1
Which is equivalent to:
7h = -14
Now let's divide both sides by 7.
7h/7 = -14/7
This is equivalent to:
h = -2
And we're done!

Second equation:
x+4+x-2 = 6 (note that the variable is only on the left-hand side...)
First, let's change order of the elements.
x+x+4+2 = 6
Now let's put parenthesis in a way that will be beneficial to us:
(x+x) + (4+2) = 6
2x + 6 = 6 subtract 6 from both sides
2x + 6 - 6 = 6 - 6
2x = 0 divide both sides by 2
2x/2 = 0/2
x = 0
And we're done.

Answer 2

Q1)

7h+1= -13

Subtract 1

7h = -14

Divide by 7

h = -2

Q2)

x+4+x-2= 6

Both of these variable are on the same side of the equation

Combine like terms

2x + 2 = 6

Subtract 2

2x = 4

Divide by 2

x = 2

Answer 3

The Cartesian Coordinate System: named after it's inventor, the great Mathematician and Philosopher Rene Decartes

Think of the X Axis as the horizontal line, and the Y Axis as the Vertical line. Where the two lines meet in the Cross-hairs=Zero
(1 To the left on X Axis are negative integers; -1,-2,-3,-4
To the Right on X Axis are positive integers: +1. +2,+3,+4

Y Axis as the Vertical line is the same except that below the Zero are negative integers; -1,-2,-3,-4
Above the Zero are positive integers: +1. +2,+3,+4

This is your "GRAPH". It's important so remember it. OK, when you have equations like:
3x-2y=6
x+y=2

Simply solve one Variable(X or Y) at a time. Example for:
3x-2y=6 if you want to solve for X, then set values for Y at -4, -3,-2, -1 while solving for X in each simply graph the results
Do the same for values of Y. Try it a couple of times and look at the graph that you get

Answer 4

Questiion 1
7h + 1 = - 13
Cover up the 7h with your finger and then ask what number must be under your finger to make the equation true.
The answer to this is - 14
Thus 7h = - 14
h = - 2

Question2
2x + 2 = 6 (cover up again)
2x = 4
x = 2

Answer 5

ANSWER ! ::

7h + 1 = -13

7h = -13 - 1

7h = - 14

h = - 14 / 7

h = - 2

ANSWER 2 ::

x + 4 + x - 2 = 6

x + x + 4 - 2 = 6

2x + 2 = 6

2x = 6 - 2

2x = 4

x = 2

Answer 6

first off its always simplet to write the equation like this 2(c+8)/3=-12 ... then start solving by multiplying both parts in the parenthesis by 2 giving you 2c+16/3=-12 then get rid of the fraction(division) by multiplying both sides by 3 giving you 2c+16=-36 .. now simply solve as an equation c+16=-18 then c= -34 and there you have it... hope thats understandable