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In a right triangle sinA=3/4 and c=17.Find a and b.

2007-05-10 11:38:22 · 2 answers · asked by RaZor 1 in Science & Mathematics Mathematics

2 answers

If sin A = 3 / 4, one side is 3 and hypotenuse is 4.
Let other side = x
4² = 3² + x²
x² = 7
x = √7
Sides are √7, 3 and 4

2007-05-11 04:45:20 · answer #1 · answered by Como 7 · 0 0

remember sin= opposite side length over hypotenuse length. Assuming c is the hypotenuse (that's how most people write it) that means that 3/4, or .75=the length of the opposite side (A)/17. Multiply both sides by 17 and u get 12.75. u can use the pythagorean theorem or more trig to get b.

2007-05-10 18:44:24 · answer #2 · answered by marsdenowen 2 · 0 1

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