what is the answer to 3x*2 +x - 10 = 0 using the quadratic formula
2007-05-10 10:12:04 · 5 answers · asked by Miles 1 in Science & Mathematics ➔ Mathematics
1.6666667 and -2
2007-05-10 10:16:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3x^2 + x - 10 = 0
x = (-b +/-âb^2 - 4ac)/2a
x = (-1 +/- â1 + 120)/6
x = (-1 +/- â121)/6
x = (-1 +/- 11)/6
x = -12/6 = -2
x = 10/6 = 5/3
2007-05-10 17:17:19 · answer #2 · answered by skm4usa 3 · 0⤊ 0⤋
-2, 5/3
2007-05-10 17:16:40 · answer #3 · answered by azulita 3 · 0⤊ 0⤋
3x*2 +x - 10 = 0
x = (-b +- â(b² - 4ac))/2a
x = (-1 +- â(1 + 120))/6
x = (-1 +- â(121))/6
x = (-1 +- 11))/6
x = -1/6 +- 11/6
x= -2, x = 5/3
.
2007-05-10 17:24:47 · answer #4 · answered by Robert L 7 · 0⤊ 0⤋
3x^2+x-10=0
x=(-1+/-â(1+120)/6
x=(-1+/-â121)/6
x=(-1-11)/6
x=-2
x=(-1+11)/6
x=10/6=5/3
x=-2, 5/3
you could do this by factoring as well
3x^2+x-10=0
(3x-5)(x+2)=0
3x-5=0
x=5/3
x+2=0
x=-2
2007-05-10 17:21:04 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋