In simplest terms...
Does...
12 a^7 b^3 c
__________
36 a^3 b^5
=
a^4 c
____
3b^2
?
2007-05-10 10:08:14 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Yes
2007-05-10 10:10:44 · answer #1 · answered by txmama423 3 · 0⤊ 0⤋
Basically, you can divide both expressions term by term. Meaning that instead of:
(12a^7b^3c)/(36a^3 b^5)
You can have:
12/36 x a^7/a^3 x b^3/b^5 x c/1
You know that 12/36 = 1/3, which is why you have the 3 in the denominator, but when you divide variables with exponents, what you're really doing is keeping the base and subtracting by the value of the exponents. Therefore:
a^7/a^3 = a^4
b^3/b^5 = b^-2 = 1/b^2
c/1 = c
Therefore, when you put it all together, you get a^4 and c in the numerator while you get 1/3 and 1/b^2 in the denominator. Hope that helps.
2007-05-10 10:13:52 · answer #2 · answered by skm4usa 3 · 0⤊ 0⤋
In english add action to fr = fraction. Isn't that simple.
2007-05-10 10:13:22 · answer #3 · answered by azrim h 5 · 0⤊ 0⤋
yes
2007-05-10 10:11:23 · answer #4 · answered by simply-remember 5 · 0⤊ 0⤋
yes
2007-05-10 10:11:11 · answer #5 · answered by Anonymous · 0⤊ 0⤋
yes well done
12/36=1/3 1 (understood)
a^7-a^3=a^4
b^5-b^3=b^2
c=c
1a^4c
---------
3b^2
2007-05-10 11:16:17 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
Yes, that's right.
2007-05-10 10:14:39 · answer #7 · answered by airtime 3 · 0⤊ 0⤋
12a^7b^3c/36a^3b^5
GCF is 12a^3b^3 dividing both the numerator & denominator by the GCF
a^4c/3b^2
YES You got it!
2007-05-10 10:13:36 · answer #8 · answered by yupchagee 7 · 0⤊ 0⤋
indeed it does. good job =]
2007-05-10 10:12:20 · answer #9 · answered by a*27 2 · 0⤊ 0⤋