How do I factor completely 9x3 - 21x6
___9x to the third power minus 21x to the sixth power
also
how do i simplify (7 ^3/4) ^2/9
2007-05-10 09:34:57 · 5 answers · asked by John S 1 in Science & Mathematics ➔ Mathematics
9x^3 - 21x^6
3 is the greatest common factor of 9 and 21, and x^3 is the smallest degree of x in any term. So you'd factor out 3 * x^3:
3x^3 ( 3 - 7x^3 )
For the simplifying, exponentiation of an exponentiation is the same as multiplying the exponents:
(7^3/4)^2/9 = 7^(3/4 * 2/9) = 7^(6/36) = 7^(1/6)
Note: This is assuming the fractions are in the exponent, i.e. you mean "7^(3/4)" and not "(7^3)/4"
2007-05-10 09:47:22 · answer #1 · answered by McFate 7 · 1⤊ 2⤋
for 9x^3 - 21x^6
3x^3(3 - 7x^3) divide out the 3x^3 being a common factor
2007-05-10 16:41:53 · answer #2 · answered by gordon_benbow 4 · 0⤊ 2⤋
9x^3 - 21x^6 = 3x^3(3 - 7x^3)
3/4 * 2/9 = 8/3
so 7^8/3
2007-05-10 16:46:27 · answer #3 · answered by Ana 4 · 0⤊ 2⤋
9x^3-21x^6
3x^3(3-7x^3)
that is 3x squared and parentheses of 3-7x raised the third..
2007-05-10 16:43:09 · answer #4 · answered by Anonymous · 0⤊ 2⤋
9x - 21x3
factor out a 3rd power
2007-05-10 16:41:06 · answer #5 · answered by Anonymous · 0⤊ 2⤋