16-36=25-45
16-16-20=25-25-20
16-16-40=25-25-40
16+25-40=25+16-40
(4-5)2=(5-4)2
(4-5)=+/- (5-4)
4-5=5-4
8=10
4=5
2007-05-10 09:12:24 · 5 answers · asked by Ramprasad Moharana 1 in Science & Mathematics ➔ Mathematics
16+25 -40 = 25+16 -40
(4-5)2 = (5-4)2
How did you get two different equations (left and right) from two similar ones?
2007-05-10 09:38:32 · answer #1 · answered by Kimbia 2 · 0⤊ 0⤋
Your mistake is in choosing 4-5 = 5-4 from the previous step.
If you look at the step (4-5)^2 = (5-4)^2, you can see that it says
1^2 = (-1)^2, which is true.
But when you take the square root on both the sides, 1 is not equal to -1. this is because the square of a number and the squre of its opposite (additive inverse) are equal; but the number is not equal to its opposite except for Zero.
So when you take the square root, what you should have actually done was to consider that 4 - 5 = -(5 - 4), or in other words,
1 = -(-1)
2007-05-10 17:23:30 · answer #2 · answered by blue rose 2 · 0⤊ 0⤋
Egads! It's right there in the problem:
(4-5)=+/- (5-4)
4-5=5-4
You explicitly drop the ± sign after introducing it. This is the fallacy, a²=b² does not imply that a=b. It could be (and is in this case) that a=-b. That's why you introduce the ± sign in the first place.
2007-05-10 17:19:02 · answer #3 · answered by Pascal 7 · 0⤊ 0⤋
the equation is right..its just getting misinterpreted in the end..
+(4-5) = -(5-4) or the other solution will be -(4-5) = +(5-4)..
this is happening because in expression (a-b)^2..after the expansion we r shifting (-b)^2 term to the other side..
2007-05-12 12:34:08 · answer #4 · answered by vijay k 1 · 0⤊ 0⤋
Hard to say.
2007-05-10 16:23:34 · answer #5 · answered by Sean H 5 · 0⤊ 0⤋