mathe questinos that will make you vomit?

Question

Rick is taking a math course and an English course. The probablities for Rick getting an A in his math course and English course are 0.6 and 0.8 respectively. The probability of getting an A in either math or English is 0.9
a) What is the probablitiy that Rick gets an A in both courses?

b) WHat is the probability that Rick will not get an A in either of the two courses?

Answer 1

Goodness, I hope your stomach has settled by now! LOL
a). The probability of getting an A in both courses
is P(A ∩ B) = P(A)*P(B) = 0.6*0.8 = 0.48.
Of course, this assumes that A and B are independent
events, i.e., that the outcome of one has no influence
on the outcome of the other. We really, don't know
this here, do we?

b). P(not A ∩ not B) = 1 - P(AUB) = 1 - 0.9 = 0.1.

Answer 2

I find it amazing that four different posters have glibly assumed that A={rick gets an A in english} and B={rick gets an A in math} are independent events, when the stipulated fact that P(A∪B)=.9 ≠ 1-(1-P(A))*(1-P(B)) = .92, proves that the events are not independent.

The key here is to note that A∪B is the disjoint union of A∩B, A\B, and B\A. So P(A∪B) = P(A∩B) + P(A\B) + P(B\A). Also, A is the disjoint union of A∩B and A\B, and B is the disjoint union of A∩B and B\A, so P(A)+P(B) = P(A∩B) + P(A\B) + P(A∩B) + P(B\A) = P(A∪B) + P(A∩B). Therefore, P(A∩B) = P(A) + P(B) - P(A∪B) = .6 + .8 - .9 = .5, not .48.

For part B, of course, the probability that he gets an A in neither course is simply 1-P(A∪B) = 1-.9 = .1 .

Answer 3

Since the probability of getting an A in both english and Math are 0.6 and 0.8 repesctively. In order to get the probability of both being an A you have to times them together therefore 0.6x0.8=0.48.
The probability of not getting an A in either class depends on the probability of getting an A in one of those classes which is 0.9. This means that the probability of NOT is 1-0.9=0.1

Answer 4

he has a 60% chance of getting an A in math, and if he does that, he then still has an 80% chance at english, so 60% x 80% or .6 x .8 = .48 or 48%

if he has a 90% chance of getting an A, he only has a 10% chance of not getting an A, so 0.1

Answer 5

A) (0.6)(0.8)=0.48 Chance.

b)since there a 0.9 chance he will get an A in either, there's a 0.1 chance he won't get an A in both.

It's not really a vomit inducing question.

Answer 6

learn how to spell and maybe someone will make a good answer for you

Answer 7

a. 0.48
b. 0.1