Solve for Z if x=y^z
2007-05-10 08:18:59 · 4 answers · asked by apshawnhunt 2 in Science & Mathematics ➔ Mathematics
Take the log of both sides:
ln x = z ln y
Divide by ln y:
z = ln x/ln y
And we are done. If only all math problems were that easy.
2007-05-10 08:25:34 · answer #1 · answered by Pascal 7 · 1⤊ 0⤋
in basic terms replace the numbers in selection to the variables (-3.17)-(8.seventy seven x -6.sixty six) you need to have the potential to parent this out. you need to attempt to a pair of your place paintings. the respond would be advantageous.
2016-11-27 00:48:13 · answer #2 · answered by leister 4 · 0⤊ 0⤋
x=y^z
Solve with logarithms.
z*ln y = ln x
z = (ln x)/(ln y)
.
2007-05-10 08:24:45 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
if x=y^z
logx()bbasey=za nswer
2007-05-10 08:24:51 · answer #4 · answered by Anonymous · 0⤊ 0⤋