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A loop of wire initially carries current 1A, which
decays exponentially due to resistance of the wire.
The changing flux of B results in non-zero electric
E field arond the wire.

The force acting on electron at rest is eE, but the force
excerted by eletron on the loop is zero, because the
loop is electrically neutral.

2007-05-10 08:10:39 · 2 answers · asked by Alexander 6 in Science & Mathematics Physics

We are talking about free electron
outside the wire.

2007-05-10 08:17:23 · update #1

2 answers

We revoked it. No seriously, just because the wire is neutral overall doesn't mean the electron doesn't interact with it. It collides and scatters off of the stuff in the metal, resulting in Ohmic heating and probably some momentum transfer. To see if the momentum transfer is significant, compare the drift velocity of electrons in the current to the thermal velocity of electrons bopping around the wire.

edit: the electromagnetic field can carry momentum as well (light has momentum), so a changing B-field can carry off momentum.

A good way to express momentum conservation in a magnetic field is to use:

p = mv + qA, where A is the vector potential of the B-field. As B-changes, so does A, so the momentum of the electron can change.

2007-05-10 08:12:45 · answer #1 · answered by Anonymous · 1 0

Congress attached a bunch of pork barrell spending to it, so Bush vetoed it.

2007-05-10 15:15:20 · answer #2 · answered by booman17 7 · 0 0

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