Formulae:
For a 30-60-90 triangle
length of the longer leg of the triangle = √3/2 * hypotnuese
length of the shorter leg of the triangle = ½*hypotnuese
Thus, the length of the longer leg of the triangle = √3/2 *18
= 9√3 mm = 15.588 mm
2007-05-10 05:28:57
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answer #1
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answered by Som™ 6
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The hypotenuse of a 30-60-ninety triangle is eighteen millimeters long. locate the size of the longer leg of thetriangle? a. 18 sq. root 3 b. 18 c. 9 sq. root 3 .......................... superb answer d. 9
2016-11-27 00:20:03
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answer #2
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answered by Anonymous
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let longer leg = y mm
sin 60° = y / 18
y = 18.sin 60°
y = 18 x √3 / 2
y = 9.√3
2007-05-10 20:20:38
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answer #3
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answered by Como 7
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First, divide by two to get the short leg length: 9 mm
Then multiply by sqrt(3) to get the long leg length: 9sqrt(3) mm
That's your answer.
2007-05-10 05:31:14
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answer #4
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answered by Skepticat 6
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the relationship of sides in a 30 60 90 triangle is always 1 to root3 to 2.
So we go (18/2)*root3 = 9*root3
2007-05-10 05:29:51
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answer #5
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answered by fredorgeorgeweasley 4
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You know the angle and the hypotenuse. From that, using sine or cosine, you can find the length of the side opposite the 60-degree side.
2007-05-10 05:29:17
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answer #6
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answered by Brian L 7
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The lengths of the other two sides are
18cos30 = 15.59mm
and 18sin30 = 9mm
so the longer side is 15.6 mm(3sf)
2007-05-10 05:30:55
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answer #7
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answered by fred 5
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cosθ = x / r
cos30 = x / 18
18cos30 = 18(x/18)
18cos30 = x
18(0.866025404) = x
15.58845726 mm = x
15.6 mm rounded to one decimal place.
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2007-05-10 05:43:42
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answer #8
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answered by SAMUEL D 7
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9*sq rt (3)
2007-05-10 05:29:50
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answer #9
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answered by Ana 4
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