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9 answers

Formulae:

For a 30-60-90 triangle

length of the longer leg of the triangle = √3/2 * hypotnuese
length of the shorter leg of the triangle = ½*hypotnuese

Thus, the length of the longer leg of the triangle = √3/2 *18
= 9√3 mm = 15.588 mm

2007-05-10 05:28:57 · answer #1 · answered by Som™ 6 · 0 0

The hypotenuse of a 30-60-ninety triangle is eighteen millimeters long. locate the size of the longer leg of thetriangle? a. 18 sq. root 3 b. 18 c. 9 sq. root 3 .......................... superb answer d. 9

2016-11-27 00:20:03 · answer #2 · answered by Anonymous · 0 0

let longer leg = y mm
sin 60° = y / 18
y = 18.sin 60°
y = 18 x √3 / 2
y = 9.√3

2007-05-10 20:20:38 · answer #3 · answered by Como 7 · 0 0

First, divide by two to get the short leg length: 9 mm

Then multiply by sqrt(3) to get the long leg length: 9sqrt(3) mm

That's your answer.

2007-05-10 05:31:14 · answer #4 · answered by Skepticat 6 · 0 0

the relationship of sides in a 30 60 90 triangle is always 1 to root3 to 2.
So we go (18/2)*root3 = 9*root3

2007-05-10 05:29:51 · answer #5 · answered by fredorgeorgeweasley 4 · 0 2

You know the angle and the hypotenuse. From that, using sine or cosine, you can find the length of the side opposite the 60-degree side.

2007-05-10 05:29:17 · answer #6 · answered by Brian L 7 · 0 2

The lengths of the other two sides are

18cos30 = 15.59mm

and 18sin30 = 9mm

so the longer side is 15.6 mm(3sf)

2007-05-10 05:30:55 · answer #7 · answered by fred 5 · 0 0

cosθ = x / r

cos30 = x / 18

18cos30 = 18(x/18)

18cos30 = x

18(0.866025404) = x

15.58845726 mm = x

15.6 mm rounded to one decimal place.

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2007-05-10 05:43:42 · answer #8 · answered by SAMUEL D 7 · 0 1

9*sq rt (3)

2007-05-10 05:29:50 · answer #9 · answered by Ana 4 · 0 0

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