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Is there a way to convert the inscribed radius to the circumscribed radius of a polygon? And visa versa

2007-05-10 05:02:06 · 5 answers · asked by platostime 1 in Science & Mathematics Mathematics

The diameters conversion will also work

2007-05-10 05:07:57 · update #1

5 answers

This I presume is for regular polygon otherwise it is meaningless.

Let the circumscribed radius be R

Let C be the centre and AB be one of sides

join AC and AB
AC = R
now we need to evaluate angle CAB

total angle = (n-2)pi
now each angle = (n-2)pi/n
angle CAB = 1/2(each angle) = (n-2)pi/(2n)

side AC = R
length of perpendicular = side of inscribed radius = r

r/R = sin((n-2)pi/2n)
this is the ratio

2007-05-11 02:58:45 · answer #1 · answered by Mein Hoon Na 7 · 0 0

First, I assume the polygon is regular with n sides. The inscribed radius is commonly called the "apothem", while the circumscribed radius is just the "radius". I will use "a" to refer to the apothem length and "r" for the radius.

The angle between the radius and the apothem is π/n. The apothem makes a right angle with the side, so the apothem and radius form a right triangle with the side. We can see that

cos(π/n) = a / r

and this is a simple formula in terms of only n relating the two lengths.

2007-05-10 12:18:08 · answer #2 · answered by airtime 3 · 0 0

The inscribed radius is called the apothem. It is a leg of a right triangle with a (circumscribed) radius as hypotenuse. By finfing the central angle of this triangle (which will be 360 divided by twice the number of sides), and using cosine (adj. leg/hypot.), you can get one from the other

2007-05-10 12:10:40 · answer #3 · answered by hayharbr 7 · 0 0

Let the length of each side be x, let the inscribed radius be r, and the circumscribed radius be R.
Then R squared = r squared + (x squared)/4.

2007-05-10 12:22:29 · answer #4 · answered by Angie F 1 · 0 0

This might be useful

2007-05-10 12:07:33 · answer #5 · answered by dudara 4 · 0 0

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