Which of the following is the greatest common factor of the terms 48s^5t^3u^2 and 40s^3tu^4?

Answer 1

GCD of 48s^5t^3u^2 and 40s^3tu^4?
48 = 8 × 6
40 = 8 × 5
GCD of 48 and 40 is 8
GCD of s^5 and s^3 is s^3
GCD of t^3 and t is t
GCD of 3 u^2 and u^4 is u^2
Therefore GCD of 48s^5t^3u^2 and 40s^3tu^4
is 8 s^3 t u^2

Answer 2

we are looking for the greatest term that will go evenly into both of them.

GCF = 8s^3tu^2

Answer 3

48=1,2,3,4,5,6.,8,12,24,48,96,144,192,240
40=1.2.4.5.8.10,20,40,80,120,160,200,240

240s^3tu^2