2007-05-10 03:41:13 · 6 answers · asked by rose 4 in Science & Mathematics ➔ Mathematics
well 6*8=48 and 6+8=14 so
m²-14m+48=(m-6)(m-8)
2007-05-10 03:44:44 · answer #1 · answered by Astral Walker 7 · 1⤊ 0⤋
m^2-14m+48
= m^2 – 8 m – 6 m + 48
= m ( m – 8 ) – 6 ( m – 8 )
= ( m – 8 )( m – 6 )
2007-05-10 11:13:13 · answer #2 · answered by Pranil 7 · 0⤊ 0⤋
m^2 - 14m + 48 = (m - 6)(m - 8)
Therefore if the equation =0
m = 6 or m = 8
2007-05-10 10:46:33 · answer #3 · answered by Doctor Q 6 · 0⤊ 0⤋
they are 8 and 6
2007-05-11 02:38:08 · answer #4 · answered by vogeti s 1 · 0⤊ 0⤋
6,8 are the factors of the above equation.
m^2-14m+48=0
m^2-6m-8m+48=0
m(m-6)-8(m-6)=0
(m-6)(m-8)=0
m=6 or m=8
2007-05-14 10:12:09 · answer #5 · answered by sriram t 3 · 0⤊ 0⤋
= (m - 8).(m - 6)
Thus (m - 8) and (m - 6) are factors.
2007-05-11 03:31:08 · answer #6 · answered by Como 7 · 0⤊ 0⤋