Solve for x: logx16=2?

Answer 1

I presume here that x is the logarithm's base.

Then logx16=2 means that x^2=16 so x=4.

Answer 2

logx16=2
=> 16 = x^2
=> 4^2=x^2
=> 4 = x

Answer 3

Another way of stating this is, "For what root of 16 is 2?" or 2^x = 16

So, x=4

Answer 4

Assume log means log base x:-
log 16 = 2
x² = 16
x = 4 (accepting +ve value for x)

Answer 5

if x is small
{
logx(16)=2
x^(logx(16))=x^2
16 = x^2
x = 4
}
else
{
e^(log(x16)) = e^2
x*16 = e^2
x = (e^2)/16
}

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Answer 6

logx16=2
x=4answer