In a certain surgery, infection occurs in 3%. The repair fails in 14% and both infection and failure occur together in 1%. What % of operations are successful and free from infection? Should it be 1-.03-.14-.01 = .82 (82%) or 1-.03-.14+.01 = .84 (84%) Thanks.
2007-05-07 05:27:55 · 2 answers · asked by BOB 7 in Science & Mathematics ➔ Medicine
The repair fails in 14% of which 1% also have an infection. The remaining 2% of patients with infection do not have failure of repair. So the total percentage of patients with complications is 16% and the percentage of uncomplicated cases is 84%.
2007-05-07 05:44:57 · answer #1 · answered by Vinay K 3 · 0⤊ 0⤋
Realistically, there is no way to determine this. While most operations are successful and infection free, you can't use statistics and say for sure that the next such surgery will follow this route.
2007-05-07 08:50:25 · answer #2 · answered by WC 7 · 0⤊ 0⤋