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excess oxygen yields N02 and H2O:
4NH3 (g) +7O2(g)-->4NO2(g) +6H2O(g)
The combustion of 28.8 of ammonia consumes___g of oxygen.
a. 94.9
b.54.1
c.108
d.15.3
e.28.8

2007-05-04 18:20:38 · 2 answers · asked by Sophia D 1 in Science & Mathematics Botany

2 answers

a. 94.9

2007-05-04 18:44:16 · answer #1 · answered by john h 7 · 0 0

Need some calcs. Divide 28.8 by 17 to get the moles of ammonia you have. Since the reaction shows that you need 7 moles of oxygen to react with 4 of ammonia, multiply the ammonia moles by 7/4 and then multiply by 32, the weight of O2.
Answer a looks closest.

2007-05-04 18:28:39 · answer #2 · answered by cattbarf 7 · 1 0

This Site Might Help You.

RE:
The combustion of Ammonia in the presence of?
excess oxygen yields N02 and H2O:
4NH3 (g) +7O2(g)-->4NO2(g) +6H2O(g)
The combustion of 28.8 of ammonia consumes___g of oxygen.
a. 94.9
b.54.1
c.108
d.15.3
e.28.8

2015-08-24 08:42:13 · answer #3 · answered by Dominica 1 · 0 0

For the best answers, search on this site https://shorturl.im/9XzDs

Find moles of NH3, use the stoichiometric ratio of NH3 to NO2, in this case 4:4 or 1:1 simplified, to find moles of NO2 Find grams of NO2 using it's molar mass

2016-04-01 08:38:15 · answer #4 · answered by Anonymous · 0 0

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