I know that the formula in finding the watts is W = V * A. But is there any limitations based in this formula? If there is, can you please tell me. But if that’s the formula, then the answer will be 1,313.5 W.. Is that right?
Likewise, can you please tell me where I can find a solar panel that produces this power (3.7 volts and 355 mA)?
Is 355 mA the same as 355 mAh?
Is this power from the solar panel ok to use (to charge) in a cell phone?
Please answer my questions..
Thank you & God Bless!
2007-05-04 01:08:55 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
You clearly weren't listening when you were told that the formula W = V*A is W (in watts), V (in volts) and A (in amps). 355 mA is 355 milliamps which is .355 Amps so the power is 1.3135 W.
Do a web search for 'solar cells' to find people who sell them.
No, 355 mA is -not- the same thing as 355 mAh. 355 mAh is a battery specification indicating how much current the battery can supply at a particular current draw.
Yes, power from a solar panel is the same as any other DC electrical power. But I wouldn't use it directly to charge a battery without some sort of charging regulator to limit the battery charging cycle. Overcharging a battery is a sure way to kill it or, at the least, damage it and reduce it's useful life.
I'm glad to be able to help the both of you.
Doug
2007-05-04 01:24:25 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
Your solar panel should deliver slightly more than 3.7 Volt or else your phone doesn't get charged.
There is a regulating circuit inside your phone that brings the voltage from your charger down to what the battery needs.
Have a look at your "normal" (wall-brick) charger:
It most likely says on it: Output 5VDC 0.7Amp., and that's what your solar panel has to deliver.
2007-05-04 10:49:56 · answer #2 · answered by Marianna 6 · 0⤊ 0⤋
a million. 3V 200mA. 1mA (milliAmp) = 0.001A; power = 3V x 0.2A = 0.6 Watts. 2. 6V 100mA is 6 x 0.a million = 0.6 Watts. 3. 9V 50mA is 9 x 0.05 = 0.40 5 Watts. 4. 12V 50mA is 12 x 0.05 = 0.6 Watts. With the three Volts one you're able to desire to connect it to a flashlight gentle bulb, that's is regarding the max you may get out of it. With the sunshine bulb, polarity does not remember, yet once you power a small transistor radio with it, then make certain the + is going to the + and the - to the -. Reversing it does not artwork and on occasion you're able to desire to wreck kit.
2017-01-09 11:23:23 · answer #3 · answered by buono 3 · 0⤊ 0⤋
Yesthere is, mA is the limitational base
when w=VA=3.7*0.355=1.3035
Rainbow Movie
355mA is diff.from 355mAh
the panel is ok for chargingof cellphone
2007-05-04 01:33:41 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Close. It's 1.31 as you are using mA rather than A. your formula is correct.
NFI about the other questions. Sorry abouth that...
2007-05-04 01:28:15 · answer #5 · answered by cifos1970 1 · 0⤊ 0⤋
3.7 v * 355mA =1313.5 mW = 1.3135W
(1000mW = 1W)
No. mAh is a measure of capacity, typically of a battery.
355mAh means "it can supply 355mA for 1 hour"
(or half as much current for twice as long.... etc)
2007-05-04 01:21:55 · answer #6 · answered by lunchtime_browser 7 · 0⤊ 0⤋
3.7V x .355A = 1.3W
2007-05-04 01:21:05 · answer #7 · answered by Bryan H 3 · 0⤊ 0⤋