Intensity level?

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What fraction of the acoustic power of a noise would have to be eliminated to lower its sound intensity level from 90 to 70 dB?

2007-05-01 19:32:23 · 2 answers · asked by hpage 3 in Science & Mathematics ➔ Engineering

2 answers

That would be a reduction of -20 dB, so
-20 = 20 log(P1/P2)
-1 = log(P1/P2)
10^(-1) = P1/P2
P1 = P2/10
so 90% of the acoustic energy would have to be removed.

HTH

Doug

2007-05-01 19:38:27 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋

Two tenths...
But why would you want to?

2007-05-02 02:35:41 · answer #2 · answered by Anonymous · 0⤊ 1⤋