How do you calculate voltage drop in overhead power lines?

Answer 1

Simple:

Measure the voltage at point A (start) and Point B ( End), and

subtract.

Best Regards

Answer 2

You would need two pieces of information:

1. The total resistance of the run of wire (in Ohms).

2. The amount of current going through the wire (in Amps).

Then its just a matter of using Ohm's law:

Amps multiplied by Ohms equals Voltage drop.

Answer 3

If the electric devices near you slow down or heat up a bit. At least 5V drop in the house supply may mean 100V drop in the overhead powerlines.

Answer 4

V = I * R , that is the basic calculation, for very long AC transmission lines there may be other losses and induction effects, but current times resistance is the simple answer. I'm guessing you actually want the hard answer, but I don't know it.

Answer 5

For Three-Phase: VD = 1.732 x K x D x I / cm

For Single-Phase: VD = 2 x K x D x I / cm

K = R x cm / 1000 (R = resistance of ohm/kFT per Table 8 of the NEC)

D = Length of the conductors in one direction

I = total connected load on the conductors

cm = circular mils

Answer 6

use this link,

http://www.stealth316.com/2-wire-resistance.htm

In a one-dimensional body, such as a wire, the relationship between current and potential can be described by Ohm's Law:

V = IR
where
V = difference of potential between two points on a wire,
I = current through a wire, and
R = resistance measured between the same two points as the potential difference.
...... fully explained .... read on

plus, there is a ready table ...
help yourself